1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 | /**************************************** @_@ Cat Got Bored *_* #_# *****************************************/ #include <bits/stdc++.h> #define loop(i,s,e) for(int i = s;i<=e;i++) //including end point #define pb(a) push_back(a) #define sqr(x) ((x)*(x)) #define CIN ios_base::sync_with_stdio(0); cin.tie(0); #define ll long long #define ull unsigned long long #define SZ(a) int(a.size()) #define read() freopen("input.txt", "r", stdin) #define write() freopen("output.txt", "w", stdout) #define ms(a,b) memset(a, b, sizeof(a)) #define all(v) v.begin(), v.end() #define PI acos(-1.0) #define pf printf #define sfi(a) scanf("%d",&a); #define sfii(a,b) scanf("%d %d",&a,&b); #define sfl(a) scanf("%lld",&a); #define sfll(a,b) scanf("%lld %lld",&a,&b); #define sful(a) scanf("%llu",&a); #define sfulul(a,b) scanf("%llu %llu",&a,&b); #define sful2(a,b) scanf("%llu %llu",&a,&b); // A little different #define sfc(a) scanf("%c",&a); #define sfs(a) scanf("%s",a); #define mp make_pair #define paii pair<int, int> #define padd pair<dd, dd> #define pall pair<ll, ll> #define fs first #define sc second #define CASE(t) printf("Case %d: ",++t) // t initialized 0 #define cCASE(t) cout<<"Case "<<++t<<": "; #define INF 1000000000 //10e9 #define EPS 1e-9 #define flc fflush(stdout); //For interactive programs , flush while using pf (that's why __c ) using namespace std; /* IDEA: Simulating a spiral is tricky .I simulated this earlier and had to handle many tricky cases. Now,I have come up with much easier solution with only 4 cases . See the figure in my blog to understand. */ int main() { int x,y; sfii(x,y); int max_layer; //Which layer I'm in actually int layer = max(abs(x),abs(y)); int xp = 1 , xn = 2 , yp = 3 , yn = 4; if(x>0 && ( (y>=0 && abs(x)>=abs(y)) || (y<0 && (abs(x) - abs(y))>=2))) // less symmetric side { max_layer = xp; } else if(x<0 && (abs(x)>=abs(y))) //much more symmetric side { //taking advantage of extra handling to make symmetric max_layer = xn; } else if(y>0 && (abs(y)>=abs(x))) // another symmetric side { max_layer = yp; } else //less symmetric side { max_layer = yn; } int ans; //Another approach if(x==0 && y==0) { ans = 0; //special case } else if(x>0 && y<=0 && x==abs(y)+1) // another special case { ans = (layer-1)*4; } else if(x<0 && y>=0 && abs(x)==y) { ans = (layer-1)*4 + 2; // safety } else if(x>0 && y>0 && (x==y)) { ans = (layer-1)*4 + 1; } else if(x<0 && y<0 && x==y) { ans = (layer-1)*4 +3; } else if(max_layer==xp) { ans = (layer-1)*4 + 1; } else if(max_layer==yp) { ans = (layer-1)*4 + 2; } else if(max_layer==xn) { ans = (layer-1)*4 + 3; } else { ans = (layer-1)*4 + 4; } pf("%d\n",ans); return 0; } |
বুধবার, ১৫ জুন, ২০১৬
EASY CF 279 A Spiral
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